Math, asked by srinivaskalepu9453, 8 months ago

find the nth derivative of x^3(sin2x)
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Answers

Answered by gowrikumar777719
1

Answer:

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Answered by meghnashit
4

Answer:

f(x)=sinx3

dxd(f(x))=dxd(sinx3)=cosx3dxd(x3)=cosx3⋅3x2=3x2cosx3

Step-by-step explanation:

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