Math, asked by sabakoppal, 11 months ago

find the nth derivative
 log(ax + b)

Answers

Answered by rajni909571
0

Answer:

y=1/ax+b•a

Step-by-step explanation:

again we find second derivative of this

y2=a^2(-1)(ax+b)^-2

then yn=a^n(-1)^n-1(n-1)!a^n/(ax+b)^n

Similar questions