Find the nth differential cofficient of sin cube x
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hey dear......
answer is......
As we know that y = sin3x
Now we are differentiation with respect to “X”
Yʹ= d/dx (sin3x)
Thus
Yʹ= 3sin2x. d/dx sinx
Finally,
we got it first derivative Yʹ= 3sin2x.cosx
And if
you want to find the nth derivative. we need to perform differentiation till
the nth term.
It
is a first derivative .and we will be find second derivative and also find the
third derivative respectively. We observe if that a pattern is followed from
first derivative to the third one. So, we can say that this pattern should be
followed till the nth derivative.
hope irs hlp uh....[^_^]
answer is......
As we know that y = sin3x
Now we are differentiation with respect to “X”
Yʹ= d/dx (sin3x)
Thus
Yʹ= 3sin2x. d/dx sinx
Finally,
we got it first derivative Yʹ= 3sin2x.cosx
And if
you want to find the nth derivative. we need to perform differentiation till
the nth term.
It
is a first derivative .and we will be find second derivative and also find the
third derivative respectively. We observe if that a pattern is followed from
first derivative to the third one. So, we can say that this pattern should be
followed till the nth derivative.
hope irs hlp uh....[^_^]
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