Question

find the nth term.....????​

Answer 1

Step-by-step explanation:

sn1/sn2=7n+1/4n+27

n/2[2a1+(n-1)d1]/n/2[2a2+(n-1)d2]=7n+1/4m+27

2a1+(n-1)d1/2a2+(n-1)d2=7n+1/4n/27

a1+(n-1/2)d1/a2+(n-1/2)d1=7n+1/4n+27

putting n-1/2=m-1,we get

a1+(m-1)d1/a2+(m-1)d2=7(2m-1)+1/4(2m-1)+27

am1/am2=14m-6/8m+23

Hence,am1:am2=14m-6:8m+23

I hope it is helpful for you.