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Nth term and 12th term of AP 3,5, 7, 9, 11....
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3, 5, 7, 9, 11............
frist term, a = 3
common difference, d = 2
12th term
a12 = a + 11d
a12 = 3 + 11×2
a12 = 3 + 22
a12 = 25
nth term
an = a + ( n – 1 ) d
an = 3 + ( n – 1 ) 2
an = 3 + 2n – 2
an = 1 + 2n
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Step-by-step explanation:
Tn=? n=12 a=3 d=5-3=2
Tn=a+(n-1)d
Tn=3+(12-1)2
Tn=3+(11)2
Tn=3+22
Tn=25
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