find the nth term and the sum of the first n terms of the AP 4,6,8....
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Step-by-step explanation:
a=4
d=6-4=2
tn=a+(n-1)d
=4+(n-1)2
=4+2n-2
=2n+2
Sn=n/2[2a+(n-1)d]
=n/2[2(4)+(n-1)2]
=n/2*2[n+3]
=n^2+3n
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