Question

find the nth term and the sum of the first n terms of the AP 4,6,8....
please answer to this question ​

Answer 1

Step-by-step explanation:

a=4

d=6-4=2

tn=a+(n-1)d

=4+(n-1)2

=4+2n-2

=2n+2

Sn=n/2[2a+(n-1)d]

=n/2[2(4)+(n-1)2]

=n/2*2[n+3]

=n^2+3n