Question

find the nth term for 1^2+(1^2+2^2)+(1^2+2^2+3^2)​

Answer 1

Answer:

N th term =1^2+2^2+3^3+...............+n^2

=n(n+1)(2n+1)/6

Answer 2

Answer:

20

Step-by-step explanation:

=1+(1+4)+(1+4+9)

= 1+5+14

= 20