Question

Find the nth term from the end of the ap. 10,7,4...., -62

Answer 1

Answer:

$a_{n-n}=13$

Step-by-step explanation:

10,7,4,....,-62 is the series.

a,b,c,d,e,f,g,h,i,.... is the series.

So common difference = b-a=7-10= -3

Fist term = a = 10

nth term = a+(n-1)d

     $a_n=a+(n-1)d=-62\\\\=>10+(n-1)-3=-62\\\\=>10-3n+3=-62\\\\=>13+62=3n\\\\=>3n=75\\\\=>n=25$

So there are 25 terms are there.

Hence the nth term from the end of AP is,

=> a+((n-n)-1)d

=>  a-d

=> 10-(-3)

=> 10+3

=> 13

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