find the nth term in 6,12,18,24
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Answer:
Here,
First term (a)= 6
common difference (d)= 6
Last term ( TN ) = 120
a + ( n - 1) × d = 1 2 0
6 + ( n - 1) × 6 = 120
6 + 6n - 6 = 120
6n = 120
n = 60
Therfore ,
Sn = n/2 × ( first term + last term)
= 10 × 126
Ans = 1260
Ans = 1 2 6 0
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