find the nth term of 1.1 2.1 3.1 4.1
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Step-by-step explanation:
Answer:-
Formula Used.
dn = an + 1 – an
an = a + (n–1)d
In the above sequence,
a = 1.1;
d1 = a2–a1 = 2.1–1.1 = 1
d2 = a3–a2 = 3.1–2.1 = 1
d3 = a4–a3 = 4.1–3.1 = 1
The difference in sequence is same and comes to be (1).
∴ The above sequence is A.P
The nth term of A.P is an = a + (n–1)d
an = a + (n–1)d = 1.1 + (n–1)(1)
= 1.1 + n–1
= 0.1 + n
hope this helps you
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