find the nth term of 1,4.9 16 and 1/3, 4/5, 7/7, 10/9
anubha148:
please help
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Answer:
n^2 , (1+3(n-1)) / (3+2(n-1))
Step-by-step explanation:
by studying the sequence u can see that its a sequence of square :
1^2, 2^2, 3^2, 4^2, ...
so nth term is n^2
and for second sequence :
1/3, 4/5, 7/7, 10/9
it would be (1+3(n-1)) / (3+2(n-1))
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