Question

Find the nth term of 14,23,32,41...

Answer 1

Answer:

9n+5

Step-by-step explanation:

difference between each number is nine

14 23 32 41

  9   9   9    

so 9n and 14-9 is 5 so 9n+5

Answer 2

The nth term of 14, 23, 32, 41 is $a_n = 9n - 5$

Solution:

Given that the sequence is:

14, 23, 32, 41

To find: nth term of given sequence

The given sequence forms a arithmetic sequence with common difference between terms "9"

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

The nth term of arithmetic sequence is given as:

$a_n - a_1 + (n - 1)d$

Where

n represents the terms location

$a_1$ is the first term of sequence

d is common difference between terms

$d = a_2 - a_1 = 23 - 14 = 9$

Substituting the values in above formula,

$a_n = 14 + (n - 1)9\\\\a_n = 14 + 9n - 9\\\\a_n = 9n - 5$

Thus the nth term is found out

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