Question

Find the nth term of a GP with:
1. first term= 5, common ratio= 2
2. first term= 1/6, common ratio= 3
with workings please! urgent!​

Answer 1

Step-by-step explanation:

First.

first term (a) = 5

second term = a*(Common ratio) = a*2

similarly, nth term = a*(common ratio)^n-1

which is equal to 5*2^(n-1)

Second.

first term (a) = 1/6

second term = a*(Common ratio) = a*3

similarly, nth term = a*(common ratio)^n-1

which is equal to (1/6)*3^(n-1)

Answer 2

Answer:

1-

arn-1

therefore 8th term =5×(2)⁸-¹

=5×(2)⁷

=5×128=640