Question

Find the nth term of a GP with:
1. second term= 1/4, common ratio= 1/2
2. sixth term=243, common ratio= -3​

Answer 1

Step-by-step explanation:

1.

for finding first term,

2nd term of GP= a×r

1/4= a×1/2

a= 1/2

So, an= a×r^(n-1)

= (1/2)(1/2)^(n-1)

= (1/4)^n-1

2.

a(r)^5= 243

a(-3)^5= 243

a= 1

Now,

an= 1×(-3)^n-1

= (-3)^n-1

= -243