Question

Find the nth term of an Ap 1/1.2, 1/2.3, 1/3.4

Answer 1

$an = a + (n - 1)d$

$a 1= \frac{1}{1.2} = \frac{10}{12}$

$a2 = \frac{1}{2.3} = \frac{10}{23}$

$d = a2 - a1 = \frac{10}{23} - \frac{10}{12}$

$appromately \: (d = 1)$

$an = \frac{10}{12} + (n - 1)1$

$an = \frac{10}{12} - 1 + n$

$an = n - \frac{1}{6}$