find the
nth
term of an AP
a) 2, 7, 10, 11
b) 16, 7, 4, 1
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a) 2,7,10,11
Here,t1=2,t2=7,t3=10,t4=11
t2 - t1 = 7-2=5
t3 - t2= 10-7=3
t4 - t3=11-10=1
The given sequence is not an A.P
b) 16,7,4,1
Here,t1=16,t2=7,t3=4,t4=1
t2 -t1=7-16=-9
t3 -t2=4-7=-3
t4 -t3=1-4=-3
The given sequence is an A.P
I hope it's correct.
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