find the nth term of AP whose sum of n term is n²+5n?
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Given: tn = 5 - 6n
Put n=1, t1= -1
n=2, t2= -7
n=3,t3= -13
Sum of n terms= n/2[2a+(n-1)d]
= n/2[2(-1)+(n-1)-6]
= n/2[-2-6n+6]
=n/2(4-6n)
=> n(2-3n)
hope you like it please please please please please please please mark has brainliest answer
Put n=1, t1= -1
n=2, t2= -7
n=3,t3= -13
Sum of n terms= n/2[2a+(n-1)d]
= n/2[2(-1)+(n-1)-6]
= n/2[-2-6n+6]
=n/2(4-6n)
=> n(2-3n)
hope you like it please please please please please please please mark has brainliest answer
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