Find the nth term of progression 625 125 25 5
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Answer:
5^(5-n)
Step-by-step explanation:
given a= 625
common ratio (r)= 5/25= 1/5
=> nth term of given GP
=> ar^n-1
= 625×(1/5)^n-1
= 625×(1/5)⁴×(1/5)^n-5
= 625×(1/625)× (1/5)^n-5
= (5)^5-n
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