find the nth term of series:
rn
10, 23,60,169,494.......
rn
(the second time difference between nos. forms a GP )
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✔️✔️we know that the n^th term:-
= x.3^n-1 + y.n + z
✔️here 3^n-1 because the common ration is 3, and it is n-1 and not n for reasons.....
✔️Put n = 1,2 and 3 to get three equations: -
10 = x + y + z ➖➖➖➖➖[1]
23 = 3x + 2y + z ➖➖➖➖➖[2]
60 = 9x + 3y + z ➖➖➖➖➖[3]
✔️Subtract eqn [1] from [2] ....
✔️ we get :-
2x + y = 13, and 2 from 3 to get 6x +?y = 37.
✔️Solve to find that question mark:-
x= 6, y = 1.
✔️ Put it in eqn 1 to get z = 3.
✔️So the n^th term of the series is:-
6.3^n-1+ n + 3....
= x.3^n-1 + y.n + z
✔️here 3^n-1 because the common ration is 3, and it is n-1 and not n for reasons.....
✔️Put n = 1,2 and 3 to get three equations: -
10 = x + y + z ➖➖➖➖➖[1]
23 = 3x + 2y + z ➖➖➖➖➖[2]
60 = 9x + 3y + z ➖➖➖➖➖[3]
✔️Subtract eqn [1] from [2] ....
✔️ we get :-
2x + y = 13, and 2 from 3 to get 6x +?y = 37.
✔️Solve to find that question mark:-
x= 6, y = 1.
✔️ Put it in eqn 1 to get z = 3.
✔️So the n^th term of the series is:-
6.3^n-1+ n + 3....
robinkuntal34:
hi
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