find the nth term of the A.P √2 , 2√2 ,3√2
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Answer:
nth term =n√2
Step-by-step explanation:
a(first term)=√2
d(common difference)=2√2-√2=√2
Tn=a+(n-1)d
=√2+(n-1)√2
=√2+n√2-√2
=n√2
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