Question

Find the nth term of the arithmetic progression 1/9,4/9,7/9,.…....​

Answer 1

Answer:

given

a=1/9

d=4/9-1/9=1/2

a+(n-1)d=0

1/9+(n-1)1/2=0

(n-1)1/2=-1/9

(n-1)=-1/9•2/1

(n-1)=-2/9

n=-2/9+1

n=-2+9/9

n=7/9