Find the nth term of the following sequence :
5 + 55 +555 + . . . . Tn
A.5(10n - 1)
B.5n(10n - 1)
C.(5/9)*(10n - 1)
D.(5/9)n *10n - 1)
Answers
Answered by
10
Answer:
heya!!
here is your answer:
5 [ 1+11+111+...+N]
Multiplying and dividing by 9
(5/9) [ 9 +99+999+...+N]
(5/9) [ (10-1) + ( 10²-1) + ( 10³-1) +...+ N]
(5/9)[ 10 + 10² + 10³ + ...+N ] -[ 1+1+1+1+...+N]
{Now 10 10² 10³ ... N are in g.p
an = 10(10^N-1 ). }
(5/9) [ 10^N -1]
hope it helps!
Answered by
4
Hi Mate!!!
The given series is neither in g.p nor in a.p so, let's make it one of the asked form.
=>. 5 [ 1 +11 +111 +...+ n]
Multiple and Divide by 9
=>. 5/9[ 9+99+999+...+n]
=>. 5/9[ (10 -1) + ( 10²-1) +( 10³-1 ) +...+ N]
=>. 5 /9 [ 10 + 10² +10³ +...+N ] - [ 1+1+1+1...N]
10 + 10² + 10³+...+ N are in g.p
=>. 5/9 [ 10^N -1]
Have a nice day
The given series is neither in g.p nor in a.p so, let's make it one of the asked form.
=>. 5 [ 1 +11 +111 +...+ n]
Multiple and Divide by 9
=>. 5/9[ 9+99+999+...+n]
=>. 5/9[ (10 -1) + ( 10²-1) +( 10³-1 ) +...+ N]
=>. 5 /9 [ 10 + 10² +10³ +...+N ] - [ 1+1+1+1...N]
10 + 10² + 10³+...+ N are in g.p
=>. 5/9 [ 10^N -1]
Have a nice day
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