find the nth term of the seris 2,7/6,1/3,-1/2
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Step-by-step explanation:
The above given series is an arithmetic progression with a = 2 and d= (-5/6)
The nth term of an arithmetic progression is given by Tn = a+(n-1)*d
Therefore the nth term of this series is of the form, Tn = 2+(n-1)*(-5/6)
or Tn= 2-(5n/6)+(5/6)
or Tn= (17/6)-(5n/6)
or Tn= (17-5n)/6
as the nth term of the series is not mentioned. the answer is as mentioned above.
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