find the nth term of this quadratic sequence 2,8,18,32
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2n^2
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we have to find nth term of this quadratic sequence ; 2 , 8 , 18 , 32...
solution : To find the nth term, we have to find the relation between the given terms.
here we see,
1st term = 2 = 2 × 1 × 1 = 2 × 1²
2nd term = 8 = 2 × 2 × 2 = 2 × 2²
3rd term = 18 = 2 × 3 × 3 = 2 × 3²
4th term = 32 = 2 × 4 × 4 = 2 × 4²
similarly 5th term = 2 × 5² = 2 × 50 = 100
...........
so nth term = 2 × n² = 2n²
Therefore the nth term must be 2n².
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