Math, asked by hattshin5, 7 months ago

find the nth term........ please find fastly​

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Answered by kumar24jun
1

Step-by-step explanation:

For Series  -3, -1, -1/3, 0, 1/5, .......... -> nth term = (n-4)/n  where n = 1,2,3........

For Series  -1, 2, -3, 4, -5,............ -> nth term = (-1)^{n}n where n = 1,2,3,.............

For Series  3, -2, 5/3, -3/2, 7/5,...... -> nth term = (-1)^{n+1}(1+(2/n))  where n = 1,2,3,..........

(I hope it will be marked as Brainliest)

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