Question

Find the number ....,..

Answer 1

Let’s get this problem solved....!!!!

Let the unit digit be b
tens digit be a

So, the number can be written in the form of :
Number = 10a + b

As in the question, the tens digit is 4x the unit digit.

Therefore,
a = 4b

As in the question, the sum of number and the units digit is 42.

Therefore,
10a + b + b = 42
10(4b) + 2b = 42
40b + 2b = 42
42b = 42

b = 1

So, in the above equation discussed,
10a + b + b = 42
10a + 1 + 1 = 42
10a = 40

a = 4

So, the number is,
10a + b = 41

Hope, it will help..!!!!

Answer 2

Answer:41

Explanation:let the unit digit be b

& Tens digit be a

So the no. can be written in the form of : 10a+b

ATQ,The tens digit is 4 times the ones digit,

Therefore,a=4b

ATQThe sum of the no. is 42

therefore,10a+b+b=42

10(4b)+2b=42

40b+2b=42

42b=42

b=1

now putting the value of b again,

10a+1+1=41

10a=40

a=4

so the req no. is 10a+b=41

Pls mark it as the brainliest.