find the number 3/4th of which exceeds its 1/12th part by 100
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Let the no be X ATQ, 3x/4 - 1x/12=100 9x-1x/12=100 8x=1200 X=1200/8 X=150
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Answer:
let the no be x
ATP
3x/4-1x/12=100
9x-1x/12 =100
8x/12=100
2x/3=100
2x=300
x=150
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