Question

find the number and mass of neutrons in 32 milligram of oxygen at STP( mass of neutrons = 1.675×10^-27 )​

Answer 1

Explanation:

32 mg=0.032g

molar mass of O2=32g

no of moles of oxygen =mass/molar mass

=0.032/32=0.001mol

OXYGEN

A=16

Z=8

A-Z=NEUTRONS

16-8=8

1 O atom contain 8 neutrons

2 O atom contains 16 neutrons

0.001×6.02×10^23 O atom contains

0.0963×10^23 neutrons

=9.63×10^21 neutrons

mass of 1 neutron=1.675×^-27 kg

mass of 9.63×10^21neutrons=16.13025×10^-6kg

Answer 2

Answer: The answer to this question is-

32 miligrams of oxygen at STP contains 9.63×$10^{21}$ neutrons and its mass is 16.13025×$10^{-6}$ kg

Explanation:

We know that -

   ⇒ 32 mg=32×$10^{-3}$ = 0.032g

And, molar mass of $O_{2}$ = 32g

Also, number of moles of oxygen,N = Given mass/Molar mass

                                                    ⇒N = 0.032/32=0.001mol

For Oxygen-

A=16 (Atomic Mass)

Z=8 (Atomic Number)

A-Z=NEUTRONS

⇒16-8=8

Since, 1 O atom contain 8 neutrons

     ∴ 2 O atom contains 16 neutrons

⇒0.001×6.02×$10^{23}$ O atom contains

⇒0.0963×$10^{23}$ neutrons

⇒9.63×$10^{21}$ neutrons

Given that-

   mass of 1 neutron=1.675×$10^{-27}$kg

  ∴mass of 9.63×$10^{21}$ neutrons = 16.13025×$10^{-6}$ kg

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