find the number and names of elements present in them and calculate the molecular masses.
1 Sulphur trioxide
2 Iron(2)sulphate
3 Ammonia
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(1). Sulphur trioxide
The formula of sulphur trioxide is SO3.
The elements present in this are- Sulphur and oxygen.
Molecular mass=SO3
= 32+3×16
=32+48
= 80
(2). Iron 2sulphate
FeSO4
= 55.8+32+ 16×4
55.8+32+64
=151.8
The elements present are-Iron, sulphur and oxygen.
(3). Ammonia
The formula is NH3
The molecular mass =14+ 3
= 17
The elements presents present are Nitrogen and Hydrogen.
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The formula of sulphur trioxide is SO3.
The elements present in this are- Sulphur and oxygen.
Molecular mass=SO3
= 32+3×16
=32+48
= 80
(2). Iron 2sulphate
FeSO4
= 55.8+32+ 16×4
55.8+32+64
=151.8
The elements present are-Iron, sulphur and oxygen.
(3). Ammonia
The formula is NH3
The molecular mass =14+ 3
= 17
The elements presents present are Nitrogen and Hydrogen.
HOPE IT WILL HELP YOU MY FRIEND!!!!
Please mark me as brainlist and sorry, I take so much of time for solving question.
Again sorry my friend.......
krish7140:
no problem don't say sorry
you have helped me
i think 2 answer in the book is 152
Yes, after round off we get 152
i hope you will understand
my friend
please mark me as brainlist
Yes
one more will give answer than only ns
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