Find the number between 1600 and 2000 which when divided by 36 and 102 will leave the remainder 5 in each case.
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l c m of 36 and 102
=36×17
=612
612×3=1836
required no =1836+5=1841
=36×17
=612
612×3=1836
required no =1836+5=1841
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