Find the number greater than 23000 that can be formed from the digits 1,2,3,4,5,6, without repeating them
Answers
Step-by-step explanation:
The solution can be broken into 2 steps:
1. The first will be to have all variations with first digit being 2. So the variation for the first digit x1. Can be one only and that is 1. The variation for the second digit x2 can be either 3,5or6 as 2 is already taken and 1cannot be as the 5 digit never should be greater than 23000.The variation for the third digit can be the other 3 digits possible. So x3 is 3. The variation for the forth digit can be the other 2 digits. Do x4 is 2. The variation of fifth digit is left to be 1. So x5 is 1. So x5 is 1. So total combination are 1*3*3*2*1=18
2. The first digit can be 3,5or6 as 1 is not allowed and 2 is taken. So x1 is 3 .x2 is the other 4. x3 is 3. x4 is 2 and x1 is 1. So the combinations are 3*4*3*3**1=72
So ultimetely , there are 72+18=90 variation in total and that are the possible list of numbers for meeting the condition.