Question

find the number less than 120 which has exactly 8 divisor.. explain in brief​

Answer 1

Answer:

In this case, let the number be N. It has factors 8 (2^3) and 20 (5*2^2) as possible factors. Thus it can be represented as

So, N= 2^(3+a)* 5^(1+b) * z^(c) where z could be any other prime number

A=3+a; B=1+b; C=c

Or

(3+a+1)*(1+b+1)*(c+1)=8 (Total no. of factors)

=> (4+a)*(2+b)*(c+1)=8

But 4*2=8

=> a=0, b=0, c=0

=> N= 2^3 * 5^1= 40

Now, listing down all factors should be simple enough: 1,2,4,5,8,10,20,40

Answer 2

Step-by-step explanation:

24 = 1, 2, 3, 4, 6, 8, 12, 24

100= 24, 30, 40, 42, 54, 56, 66, 70, 78, 88.