Question

Find the number nearest to 100000 and greater than 100000 which is exactly divisible by 8,5,21

Answer 1

Answer:

Hey Here is your answer.

First,

Takeout the LCM of 8,15,21 and when takeout the LCM then it is 840.

Now divide 100000 by 840 so then it will get reminder as 40 after division.

So now we will compensate the 40.

Now then we will get the number more than 100000 so we will get

100000+840-40

100000+800

100800.

So 100800 is required number which is divisible by the numbers 8,15,21.

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