Math, asked by bikrantadutta8, 6 days ago

find the number nearest to 100000 but greater than 10000 which is extra divisible by each of 8 ,15 and 21

Answers

Answered by routjyoti24

1

Answer:

100000+840-40 = 100800 is the rquired number, which is divisible by 8, 15 and 21.

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