find the number nearest to 1000000 which is exactly divisible by 12 18 32 and 63
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First of all take the LCM of 8, 15 and 21, which will be 840.
Now divide 100000 by 840, you will get remainder 40. So we have to compensate 40.
Now your requirement is the number which is greater than 100000, so you will get it by
100000+840-40 = 100800 is the rquired number, which is divisible by 8, 15 and 21.
this is just a example
I hope this will help you
Now divide 100000 by 840, you will get remainder 40. So we have to compensate 40.
Now your requirement is the number which is greater than 100000, so you will get it by
100000+840-40 = 100800 is the rquired number, which is divisible by 8, 15 and 21.
this is just a example
I hope this will help you
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