Question

find the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8,15 and 21

Answer 1

Answer:

The number which is divisible by 8, 15, and 21 is also divisible by the L.C.M of the number 8, 15 and 21. The L. C. M of 8, 15, and 21 is calculates as:  

Thus, the number less than 110000 and nearest to 110000 that is divisible by 840 is 110000 – 800 = 109200

Now, 109200 is also greater than 100000.

Thus, the number nearest to 110000 and greater than 100000 which is exactly divisible by 8, 15, and 21 is 109200.

Step-by-step explanation: