find the number nearest to 110000 par greater than 100000 which is exactly divisible by each of 8,15 and 21
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take LCM of 8,15 and 21 it's equal to
840 so no is form of 840n
now
100000<=840n <=110000
119.xx<=n<=130.95
as number should be nearest to 110000 so and n should be integer so
n=130
hence number is 840 *130
109200
840 so no is form of 840n
now
100000<=840n <=110000
119.xx<=n<=130.95
as number should be nearest to 110000 so and n should be integer so
n=130
hence number is 840 *130
109200
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