Question

Find the number nearest to 12193 which is exactly divisible by product of the first four prime number

Answer 1

First we would be multiplying the first 4 prime no. which are 2*5*7*3 which is equal to 210.

So now by devising the no. by 12193 we would be getting a remainder of 13. if we remove 13 from 12193 we would be perfectly devising the no. 12193.

so the no. perfectly divisible by 210 under 12193 is 12180.

adding 210 to 12180 we would be getting the no. perfectly divisible by 210 which is 12390