Question

Find the number nearest to 999 but Greater than 999 which is exactly divisible by 5,4 and 10​

Answer 1

Let us get the LCM of 8,12 and 18.

8=2^2^2.

12=2*2*3.

18=2*3*3.

LCM=2*2*2*3*3*=72.

By dividing 999 by 72 you get 13 as quotient with a remainder 63.

So you have to add 72–63=9 to 999 to get the number divisible by 8,12 and 18.

The number we want is =999 +9 =1008.

Answer 2

The number is 1000.

Given:

Number 5,4 and 10

To find:

Find the number nearest to 999 but Greater than 999 which is exactly divisible by 5,4 and 10​

Solution:

To find the number divisible, first we have to find LCM of 5,4 and 10

We will find LCM by prime factorisation method:

5 = 5*1

4 = 2*2*1

10 = 1 * 2* 5

Now, we will take highest powers which are 2²,1 and 5

LCM = 1*2*2*5 = 20

Now, we have to find a multiple of 20 which is greater than 999

The next number is 1000

We will check if it is divisible by 20 or not.

1000/20 = 500

Hence, it is divisible.

So, the number is 1000.

#SPJ2