Math, asked by malavjodhraj, 1 year ago

find the number of 20 cm×15cm bricks required to have a 45m × 20m len. find the cost of the bricks at the rate of rupees 900 per thousand

Answers

Answered by adityarana8027
21
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Answered by wifilethbridge
8

The cost of the bricks at the rate of rupees 900 per thousand Rs.27000 and the number of 20 cm×15cm bricks required is 30000

Step-by-step explanation:

Length of wall = 45 m = 4500 cm

Breadth of wall = 20 m = 2000 cm

Area of wall = Length \times Breadth = 4500 \times 2000 =9000000 cm^2

Length of brick = 20 cm

Breadth of brick = 15 cm

Area of brick = 20 \times 15 = 300 cm^2

No. of bricks required = \frac{9000000}{300}=30000

Cost of 1000 bricks = Rs.900

Cost of 1 brick =\frac{900}{1000}

Cost of 30000 bricks= \frac{900}{1000} \times 30000=27000

Hence the cost of the bricks at the rate of rupees 900 per thousand Rs.27000 and the number of 20 cm×15cm bricks required is 30000

#Learn more:

A lane 180m long and 5m wide is to be paved with bricks, of length 20cm and breadth 15cm find the cost of brick that are required, at the rate of rupee 750 per thousand.

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