Find the number of 4-digit positive integers divisible by either 3 or 7.
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We need to find 4 digit numbers whose digits product is divisible by 3.
At least one of the digit is divisible by 3.
⇒ Required = Total − No digit is divisible by 3.
⇒ Total number of 4 digit numbers =9×10×10×10
=9000.
No digit is divisible by 3 →0,3,6,9 must not appear.
∴ Numbers should be formed using only 1,2,4,5,7,8=6 numbers.
⇒ No. of ways =6×6×6×6=6
4
=1296.
⇒ Required =9000−1296
=7704.
Hence, the answer is 7704.
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At least one of the digit is divisible by 3.
⇒ Required = Total − No digit is divisible by 3.
⇒ Total number of 4 digit numbers =9×10×10×10
=9000.
No digit is divisible by 3 →0,3,6,9 must not appear.
∴ Numbers should be formed using only 1,2,4,5,7,8=6 numbers.
⇒ No. of ways =6×6×6×6=6
4
=1296.
⇒ Required =9000−1296
=7704.
Hence, the answer is 7704.
Mark me plz
Answered by
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Step-by-step explanation:
We need to find 4 digit numbers whose digits product is divisible by 3.
At least one of the digit is divisible by 3.
⇒ Required = Total − No digit is divisible by 3.
⇒ Total number of 4 digit numbers =9×10×10×10
=9000
No digit is divisible by 3 →0,3,6,9 must not appear.
∴ Numbers should be formed using only 1,2,4,5,7,8=6 numbers.
No. of ways =6×6×6×6=6
4
=1296.
⇒ Required =9000−1296
=7704.
Hence, the answer is 7704.
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