Question

Find the number of 6-digit odd numbers which have 3 digits even and 3 digits odd , if each digit is to be used only once.

Answer 1

Hope it helps...!!!!

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✔️Number of ways of selection of 3  even number from 0,2,4,6,8  is  5C3

✔️Number of ways of selection of 3 odd number from 1,3,5,7,9  is  5C3

✔️Total ways =5C35C3 6!

✔️But this number also include zero at first place

 
✔️total number in which zero at place place = 5C34C2 5!

 

✔️ So total number  =5C35C3 6! -5C34C2 5!

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