Math, asked by kumarlina26, 10 months ago

find the number of a square tiles of 15cm required for covering the floor room length 9m and 6m wide. find also the cost of the tiles required.if one tile costs rs. 4.50.

Answers

Answered by HeAvEnPrlnCesS
6

Answer:

Answer:

2400 tiles

Rs 10800

Step-by-step explanation:

Area of floor = length * width

Area of floor = 9 * 6 = 54 m^2

Area of a tile = 15 cm * 15cm

= (15/100) m * (15/100) m

= 225/10000 m^2

Number of tile required to cover floor = floor area / tile area

Number of tile required to cover floor = 54 / (225/10000)

= 540000/225

= 2400 tiles

Cost of one tile = Rs 4.5

cost of 2400 Tiles = 2400 * 4.5 = Rs 10800

Answered by Sreehari3899
0

2400 tiles

Rs 10800

Step-by-step explanation:

Area of floor = length * width

Area of floor = 9 * 6 = 54 m^2

Area of a tile = 15 cm * 15cm

= (15/100) m * (15/100) m

= 225/10000 m^2

Number of tile required to cover floor = floor area / tile area

Number of tile required to cover floor = 54 / (225/10000)

= 540000/225

= 2400 tiles

Cost of one tile = Rs 4.5

cost of 2400 Tiles = 2400 * 4.5 = Rs 10800

Similar questions