Question

Find the number of air molecules in a room of volume 12 m3

. Given 1 mole of air at

N.T.P. occupies a volume of 22.4 liters.​

Answer 1

Answer:

Atomic volume =43πR3×N=43π(0.5×10−10)3×6.023×10233.154×10−7m3.

Molar volume =22.4litre=22.4×10−3m3.

Molar volumeAtomic volume=22.4×10−33.154×10−7=7.1×104

This ratio is large due to large intermolecular separtions.

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