find the number of all 2 digit numbers divisible by 3
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Answered by
8
Answer:
12+15+18....99
a1=12,l=99,d=3
l=a+(n-1)d
99=12+(n-1)3
3(n-1)=87
n-1=29
n=30
Answered by
0
by divisiblety method
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