Question

Find the number of all 2 digit numbers divisible by 3. From chapter quadratic polynomial.​

Answer 1

Answer:

30

Step-by-step explanation:

First 2 digit number divisible by 3 = 12

Last 2 digit number divisible by 3 = 99

A.P = 12, 15, 18, .... ,99

nth term in an AP = a+(n-1)d

a = first term in AP = 12

d = common difference = 3

Consider the last term i.e., 99

99 = 12+(n-1)3

3(n-1) = 99-12

n-1 = 87/3

n = 29+1

n = 30

Hence, there are 30 terms in the AP