Find the number of all 2 digit numbers divisible by 3. From chapter quadratic polynomial.
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Answer:
30
Step-by-step explanation:
First 2 digit number divisible by 3 = 12
Last 2 digit number divisible by 3 = 99
A.P = 12, 15, 18, .... ,99
nth term in an AP = a+(n-1)d
a = first term in AP = 12
d = common difference = 3
Consider the last term i.e., 99
99 = 12+(n-1)3
3(n-1) = 99-12
n-1 = 87/3
n = 29+1
n = 30
Hence, there are 30 terms in the AP
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