find the number of all 3 digit natural number divisible by 9
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Hey,
Three digit which is divisible by 9(a) =108
second =117
difference between them(d)=9
and last digit divisible = 999
AP = 108,117, 126,...,999
n= no of term
term on which 999 comes = a +(n-1)d
999=108 +(n-1)9
999=108 + 9n -9
999 - 108 +9 =9n
900 = 9n
n = 100
three digit numbers which are divisible by 9 are 100.
HOPE IT HELPS YOU:-))
Three digit which is divisible by 9(a) =108
second =117
difference between them(d)=9
and last digit divisible = 999
AP = 108,117, 126,...,999
n= no of term
term on which 999 comes = a +(n-1)d
999=108 +(n-1)9
999=108 + 9n -9
999 - 108 +9 =9n
900 = 9n
n = 100
three digit numbers which are divisible by 9 are 100.
HOPE IT HELPS YOU:-))
Answered by
2
the sum of numbers that divide by 9 equals to 9 or divides by 9.
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