Math, asked by aaryanpathak5678, 8 months ago

Find the number of all 6-digit numbers such that all the digits of each number are selected from the set {1, 2, 3, 4} and any digit that appears in the number appears at least twice​

Answers

Answered by Anonymous
5

answer

  • Total 6 digit numbers = 9X10X10X10X10X10 =9000000

  • Possible numbers when no repetition is allowed is
  • 9X9X8X7X6X5= 136080

  • So required number is 763920 by subtracting the above two numbers

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