find the number of all natural numbers between 100 to 400 which are divisible by 3
Answers
Answer:
8729
Step-by-step explanation:
We need to find least number and greatest number divisible by 7 between 200 and 400.
Then we'll form an A.P with,
=
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Now, divide 400 by 7.
If you don't get any remainder then 400 is divisible by 7 and hence largest divisible number but if you get a remainder (which you will), then subtract the remainder from 400 to get largest number.
In this case, we get remainder = 1
Subtracting remainder from 400 = 400-1 = 399
Hence, largest number divisible by 7 is 399
=> ✔️
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Now we'll divide 200 by 7.
This time if we get a remainder not equal to 0 then we'll subtract it from 200 and add 7.
The remainder we get is 4.
Now,
=> 200 - 4 + 7
=> 200 + 3
=> ✔️
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Now,
We know that,
a = 203
l = 399
d = 7
n = ?
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Using the formula,
✅✅
=>
=>
=>
=>
=>
=> ✔️
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Now,
We need to calculate sum of all terms.
Using the formula,
✅✅
=>
=>
=>
=> ✔️✔️
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Hence, Sum of All Natural Numbers divisible by 7 between 200 and 400 is 8729.