Question

Find the number of all the possible three digit numbers which can be formed by the digit 4,6 and 8 where the repetition of the digit is not allowed

Answer 1

Answer:

468;684;864;486;648;846

Answer 2

Answer:

Well it is easy to solve it. You want a 3-digit number that contains 0,6 and 9 , but with no repetition.

For the first digit you have two candidates: 6 and 9 . Zero can’t be the first digit.

For the second digit you have two options because you used one for the first number.

For the third number there is only one option.

So the result is:

2×2×1=4 The answer is 4 . If you could use more digits, then the result would logically be bigger. You can have:

604

640

460

406

I hope this answered your question.